Theorem
Points equidistant from two intersecting lines form a pair of bisectors
Geometry • Line • Angles at a Point
Statement
Two intersecting lines make four angles at their point of intersection. A point is equidistant from both lines exactly when it lies on one of the angle bisectors, and since vertically opposite angles share a bisector the four angles supply only two bisecting lines, which are perpendicular to each other. The locus is therefore a pair of perpendicular straight lines through the point of intersection, not a single line.
How to use it
- 1Take the two lines as the coordinate axes: the condition becomes , whose solution set is together with .
- 2Inside a triangle only the internal bisectors are wanted, which is why the incentre is one point; the external bisectors give the excentres.
- 3If the two lines are parallel instead of intersecting, the locus collapses to the single line midway between them.
Worked example
Two lines meet at the origin along and . Find every point of the line that is equidistant from both lines.
Step-by-step
- 1distance to is ; distance to is
Why: Distance to an axis is the absolute value of the other coordinate.
- 2, so or
Why: Equidistance gives two solutions, one on each bisector.
- 3the points are and
Answer
and
Watch out
Answering 'a straight line' is the standard error: the locus has two branches, because a point can sit in either of the two pairs of vertically opposite angles. Distances here are perpendicular distances to the lines, not to the point of intersection.
Builds on
Also known as
locus equidistant from two lines, pair of angle bisectors, internal and external bisector, angle bisector locus, bisectors of two intersecting lines are perpendicular